Tennis balls are routinely sold in cylindrical cans with 3 stacked balls. Given such a can, which will be greater, the height of the can or its circumference?
ANSWER: Obviously, this question wouldn't be asked as a puzzle if appearances weren't deceiving (i.e. the can "looks" easily taller than the circumference, but looks are deceptive) -- the math tells the story: Height of the can is approximately 3 x d (diameter) or 6r (radius). Circumference of the can is approximately 2πr. With pi being approximately 3.14, the circumference will thus be slightly larger than the height (and if you don't believe it, find a can and do the measurements yourself!)
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ANSWER: Obviously, this question wouldn't be asked as a puzzle if appearances weren't deceiving (i.e. the can "looks" easily taller than the circumference, but looks are deceptive) -- the math tells the story: Height of the can is approximately 3 x d (diameter) or 6r (radius). Circumference of the can is approximately 2πr. With pi being approximately 3.14, the circumference will thus be slightly larger than the height (and if you don't believe it, find a can and do the measurements yourself!)
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